澳洲奥数题目

realjian

我的一位澳洲朋友问我一道他孩子的澳洲奥数题。我看了半天没有弄明白。 烦请足迹网的各位高人指点一下。
多谢了！
Your Task
You will assess the probability of a certain hand winning after the starting hands are dealt. You only need to consider two players at a time. (At no point are we considering betting or folding playing a part in winning)
Starting points:
-Try and watch some games of Texas hold at either on television or on youtube. They show the probabilities throughout each game.
-Look at the different possible starting hands, e.g. pairs, same suit, etc.
-Look at the following example with two players; （照片请看附件的图片）
If player 1 has two fives as his starting hand and player 2 has an ace and a king

-What is the possibility that player 1 will win this deal after the 5 community cards are dealt?
-Select some different starting hands, two at a time, and calculate the probability that one hand will win – this will form the majority of your assignment.

jungle

LZ发的这个东东是一道题？我倒～这是培养职业赌徒的题吧。

基于已有的2张牌，计算发完5张牌之后获胜的几率，这需要非常复杂的计算。LZ先看看规则再说吧。
http://boardgames.about.com/cs/poker/a/texas_rules.htm

比大小的规则：
http://boardgames.about.com/cs/poker/a/poker_hands.htm

我个人认为出给中学生的话，这个作为一个计算机编程的题倒是比较合适。人工计算就有点变态了。

Artcore

一副牌有52张, 去掉55和AK (非同花的)还有48张.

顺下还有3个A, 3个K.

下一张牌是A或K的可能发生是6/48, 不是A或K的概率是42/48. 所以5张牌不是A&K的机率是:

(42/48)x(41/47)x(40/46)x(39/45)x(38/44)= 49.68%

那拿到一个A或K的概率就是1-49.68% = 50.32%

当然接下来的5张牌和A&K或55也可能凑成顺子,同花,三张,俘虏,炸弹,同花顺等等, 这些概率就不考虑了.

[ 本帖最后由 Artcore 于 2009-9-11 14:41 编辑 ]

avatar

没有这么简单吧，如果不是AK但是个5，也很重要啊

toolaa

这个好像要每张牌逐次算，同花是不可能有的了。

realjian

多谢大家的热心回复。我也认为这是个非常有用的问题。下次如果去STAR CITY 或者CROWN话、就心理有数了:) 。请大家绝续献智献慧。

dayang

有意思，HD Channel One 上有时有poker competition，每拿一张牌左下教都有个胜率百分比，不知道是怎么算出来的